(2x^2+7x-4)*(x^2+1)=0

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Solution for (2x^2+7x-4)*(x^2+1)=0 equation: 


Simplifying
(2x2 + 7x + -4)(x2 + 1) = 0

Reorder the terms:
(-4 + 7x + 2x2)(x2 + 1) = 0

Reorder the terms:
(-4 + 7x + 2x2)(1 + x2) = 0

Multiply (-4 + 7x + 2x2) * (1 + x2)
(-4(1 + x2) + 7x * (1 + x2) + 2x2 * (1 + x2)) = 0
((1 * -4 + x2 * -4) + 7x * (1 + x2) + 2x2 * (1 + x2)) = 0
((-4 + -4x2) + 7x * (1 + x2) + 2x2 * (1 + x2)) = 0
(-4 + -4x2 + (1 * 7x + x2 * 7x) + 2x2 * (1 + x2)) = 0
(-4 + -4x2 + (7x + 7x3) + 2x2 * (1 + x2)) = 0
(-4 + -4x2 + 7x + 7x3 + (1 * 2x2 + x2 * 2x2)) = 0
(-4 + -4x2 + 7x + 7x3 + (2x2 + 2x4)) = 0

Reorder the terms:
(-4 + 7x + -4x2 + 2x2 + 7x3 + 2x4) = 0

Combine like terms: -4x2 + 2x2 = -2x2
(-4 + 7x + -2x2 + 7x3 + 2x4) = 0

Solving
-4 + 7x + -2x2 + 7x3 + 2x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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